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Question: Answered & Verified by Expert
If the matrix A=02K-1 satisfies AA3+3I=2I, then the value of K is
MathematicsMatricesJEE MainJEE Main 2021 (27 Aug Shift 1)
Options:
  • A 12
  • B 1
  • C -1
  • D -12
Solution:
2743 Upvotes Verified Answer
The correct answer is: 12

AA3+3I=2I

A2=02K-102K-1

=2K-2-K2K+1

A3=2K-2-K2K+10-1K2

=-2K4K+22K2+K-2K-2K-1

A4=2K-2-K2K+12K-2-K2K+1

=4K2+2K       -4K-4K-2-2K2-2K2-K  2K+4K2+1+4K

A4+3AI=2I

2I=4K2+2K-8K-2-4K2-K4K2+6K+1+302K-11001

2I=4K2+2K-8K-2-4K2-K4K2+6K+1+302K-1

2I=4K2+2K6-8K-23K-K-4K24K2+6K+1-3

  4-8K=0

K=12

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