If the maximum concentration of P b C l 2 in water is 0.01 M at 25 ° C , its maximum concentration in 0.1 M NaCl will be

Question

If the maximum concentration of P b C l 2 in water is 0.01 M at 25 ° C , its maximum concentration in 0.1 M NaCl will be, 2 × 1 0 - 3 M, 1.6 × 1 0 - 2 M, 1 × 1 0 - 4 M, 4 × 1 0 - 4 M

MARKS App · Accepted Answer

P b C l 2 ⇌ P b 2 + + 2 C l K s p = [ P b 2 + ] [ C l - ] 2 = ( 0.01 ) ( 2 × 0.01 ) 2 K s p = 4 × 1 0 - 6 P b C l 2 ⇌ P b 2 + ( a q ) 0 S + 2 C l - ( a q ) 0.1 ( 2 S + 0.1 ) K sp = [ Pb 2+ ] [Cl − ] 2 0.1 + 2 S ≈ 0.1 4 × 1 0 - 6 = S × ( 0.1 ) 2 S = 4 × 1 0 - 4 M Maximum concentration of P b C l 2 in 0.1 M NaCl is 4 × 1 0 - 4 M .

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