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If the mean, mode and S.D. of a frequency distribution are 41, 45 and 8 respectively, then its Pearson's coefficient of skewness is
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\(\frac{-1}{2}\)
\(-\frac{1}{2}\), We have \(\mathrm{S}_{\mathrm{K}}=\frac{\text { Mean }- \text { Mode }}{\mathrm{S} . \mathrm{D} \text {. }}\)
\(\frac{41-45}{8}=-\frac{1}{2}\)
\(\frac{41-45}{8}=-\frac{1}{2}\)
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