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Question: Answered & Verified by Expert
If the minimum value of $f(x)=x^2+2 b x+2 c^2$ is greater than the maximum value of $g(x)=-x^2-2 c x+b^2$ for all real $x$ then
MathematicsQuadratic EquationAP EAMCETAP EAMCET 2018 (24 Apr Shift 2)
Options:
  • A $|c|>\sqrt{2}|b|$
  • B $|c| \sqrt{3}>|b|$
  • C $-1 < c < \sqrt{2} b$
  • D $\frac{1}{\sqrt{2}} < c < |b|$
Solution:
2849 Upvotes Verified Answer
The correct answer is: $|c|>\sqrt{2}|b|$
No solution. Refer to answer key.

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