Search any question & find its solution
Question:
Answered & Verified by Expert
If the modulation index of an amplitude modulated wave is changed from 0 to 1 , then the transmitted power will be
Options:
Solution:
1975 Upvotes
Verified Answer
The correct answer is:
increased by $50 \%$
The transmitted power in AM wave is
$P_t=\left(1+\frac{\mu^2}{2}\right) P_c$
where $\mu$ is the modulation index and $P_c$ is the power in carrier wave.
When $\mu=0, P_t=P_c$
and when $\mu=1, P_t=\left(1+\frac{1}{2}\right) P_c=\frac{3}{2} P_c$
$\therefore$ The percentage increase in transmitted power
$=\frac{\frac{3}{2} P_c-P_c}{P_c} \times 100 \%=\frac{1}{2} \times 100 \%=50 \%$
$P_t=\left(1+\frac{\mu^2}{2}\right) P_c$
where $\mu$ is the modulation index and $P_c$ is the power in carrier wave.
When $\mu=0, P_t=P_c$
and when $\mu=1, P_t=\left(1+\frac{1}{2}\right) P_c=\frac{3}{2} P_c$
$\therefore$ The percentage increase in transmitted power
$=\frac{\frac{3}{2} P_c-P_c}{P_c} \times 100 \%=\frac{1}{2} \times 100 \%=50 \%$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.