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If the molecular weight of two gases are $M_1$ and $M_1$, then at a temperature the ratio of root mean square velocity $v_1$ and $v_2$ will be
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The correct answer is:
$\sqrt{\frac{M_2}{M_1}}$
$v_{r m s}=\sqrt{3 R T / M} \Rightarrow \frac{v_1}{v_2}=\sqrt{\frac{M_2}{M_1}}$
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