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If the normal to the curve $y=f(x)$ at the point $(3,4)$ make an angle $3 \pi / 4$ with the positive $x$-axis, then $f(3)$ is
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1
Hints: $\frac{d y}{d x}=f^{\prime}(x)$, Slope of normal $=-\frac{1}{f^{\prime}(x)},-\frac{1}{f^{\prime}(3)}=\tan \frac{3 \pi}{4}=-1$ $f^{\prime}(3)=1$
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