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If the normal to the curve $y=f(x)$ at the point $(3,4)$ makes and angle $\left(\frac{3 \pi}{4}\right)^{\mathrm{C}}$ with positive $\mathrm{X}$-axis, then $f^{\prime}(3)$ is equal to
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$1$
$\begin{aligned} & \text { Slope of normal }=\frac{-1}{f^{\prime}(x)} \\ & \Rightarrow \tan \left(\frac{3 \pi}{4}\right)=\frac{-1}{f^{\prime}(3)} \\ & \Rightarrow-1=\frac{-1}{f^{\prime}(3)} \\ & \Rightarrow f^{\prime}(3)=1\end{aligned}$
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