If the nucleus 1 3 2 7 Al has a nuclear radius 3.6 fm, then what would be the approximate value of nuclear radius (in fm) of 3 2 12 5 Te ?

Question

If the nucleus 1 3 2 7 Al has a nuclear radius 3.6 fm, then what would be the approximate value of nuclear radius (in fm) of 3 2 12 5 Te ?,

MARKS App · Accepted Answer

Nuclear radius, R = ( R 0 ) A 1/3 where A is the mass number. ∴ R ⁡ Te ⁡ R ⁡ Al ⁡ = A ⁡ Te ⁡ A ⁡ Al ⁡ 1 / 3 = 1 2 5 2 7 1 / 3 = 5 3 or R ⁡ Te = 5 3 × R ⁡ Al ⁡ = 5 3 × 3 · 6 = 6 fm Given R ⁡ Al ⁡ = 3 · 6 fm

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