Given that, number of elements in the sets $G$ and $A$ are 3 and 4 respectively.
(A) The number of non bijective function from $G \times G$ to $G=3^9=19683$


(B) $A$ to $A$

Here, $a$ has 4 choice, $b$ has $3, c$ has 2 and $d$ has 1 choice.
So, number of bijective functions from $A$ to $A$ is
$$
=4 \times 3 \times 2 \times 1=24
$$
(C) $G$ to $G \times A$

So, number of function from $G$ to $G \times A$ is
$$
=12^3=1728
$$
(D) $A$ to $A \times A$
The number of surjective from $G$ to $G \times A$ i.e. 4 to 16 is 0
So, $\mathrm{A} \rightarrow \mathrm{V}, \mathrm{B} \rightarrow \mathrm{I}, \mathrm{C} \rightarrow \mathrm{III}, \mathrm{D} \rightarrow$ II.