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Question: Answered & Verified by Expert
If the number of terms in the expansion of 1+x1011+x2-x100 is n, then the value of n25 is equal to
MathematicsBinomial TheoremJEE Main
Solution:
1298 Upvotes Verified Answer
The correct answer is: 8.08

1+x1011+x2-x100
=1+x1+x1-x+x2100
=1+x1+x3100
=1×1+x3100+x×1+x3100
So, the number of terms=( 101 terms of the form x3k ) + (101 terms of the form x3k+1 )
=202 terms

n=202

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