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Question: Answered & Verified by Expert
If the origin lies between zeroes of the  polynomial fx=x24-ax+a2+a-2, then the number of integral value(s) of a is
MathematicsQuadratic EquationJEE Main
Options:
  • A 1
  • B 2
  • C 3
  • D more than 3
Solution:
2099 Upvotes Verified Answer
The correct answer is: 2
For zeroes on either side of the origin.
Opening upward parabola
f0<0
a2+a-2<0
a+2a-1<0
-2<a<1
2 integers i.e. -1,0

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