Search any question & find its solution
Question:
Answered & Verified by Expert
If the pair of straight lines $x^2-2 p x y-y^2=0$ and $x^2-2 p x y-y^2=0$ be such that each pair bisects the angle between the other pair, then
Options:
Solution:
2939 Upvotes
Verified Answer
The correct answer is:
$p q=-1$
$p q=-1$
Equation of bisector of both pair of straight lines,
$p x^2+2 x y-p y^2=0$
$q x^2+2 x y-q y^2=0$
From (1) and (2). $\frac{\mathrm{q}}{1}=\frac{2}{-2 \mathrm{p}}=\frac{-\mathrm{q}}{-1} \Rightarrow \mathrm{pq}=-1$
$p x^2+2 x y-p y^2=0$
$q x^2+2 x y-q y^2=0$
From (1) and (2). $\frac{\mathrm{q}}{1}=\frac{2}{-2 \mathrm{p}}=\frac{-\mathrm{q}}{-1} \Rightarrow \mathrm{pq}=-1$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.