Concentration of calcium lactate = $0.005 \mathrm{M}$

concentration of lactate ion = $= (2 \times 0.005) \mathrm{M}$

Calcium lactate is a salt of weak acid + strong base

$\therefore$ Salt hydrolysis will take place for a basic salt:

$$\begin{gathered} \Rightarrow \mathrm{pH}=7+\frac{1}{2}\mathrm{pKa}+\frac{1}{2}\mathrm{logC} \\ =7+\frac{1}{2}\times 5+\frac{1}{2}\log (0.01) \\ =85 \times {10}^{-1} \end{gathered}$$