Search any question & find its solution
Question:
Answered & Verified by Expert
If the potential energy of a hydrogen atom in the first excited state is assumed to be zero, then the total energy of \(n\) \(=\infty\) state is,
Options:
Solution:
1039 Upvotes
Verified Answer
The correct answer is:
\(6.8 \mathrm{eV}\)
Hint : Potential energy in 1 st emited stage \(\left(\mathrm{U}_2\right)=-6.8 \mathrm{eV}\). When \(U_2\) is assumed to be zero then potential energy in \((n=\infty)\)
will be \(6.8 \mathrm{eV}\)
so, total energy for \((n=\infty)=6.8 \mathrm{eV}\)
will be \(6.8 \mathrm{eV}\)
so, total energy for \((n=\infty)=6.8 \mathrm{eV}\)
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.