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If the pressure of a gas increases by $2 \%$ at constant volume, then its temperature
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The correct answer is:
increases by $2 \%$
Using ideal gas equation,
$\mathrm{PV}=\mathrm{nRT}$
Volume is constant,
$\begin{aligned} & \frac{P}{T}=\frac{n R}{V}=\text { constant } \\ & P \propto T\end{aligned}$
If pressure increase by $2 \%$ than temperature is also increase by $2 \%$
$\mathrm{PV}=\mathrm{nRT}$
Volume is constant,
$\begin{aligned} & \frac{P}{T}=\frac{n R}{V}=\text { constant } \\ & P \propto T\end{aligned}$
If pressure increase by $2 \%$ than temperature is also increase by $2 \%$
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