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Question: Answered & Verified by Expert
If the radius of the first orbit of hydrogen atom is a0, then de Broglie’s wavelength of electron in 3rd orbit is
ChemistryStructure of AtomJEE MainJEE Main 2023 (06 Apr Shift 2)
Options:
  • A πa06
  • B πa03
  • C 6πa0
  • D 3πa0
Solution:
2733 Upvotes Verified Answer
The correct answer is: 6πa0

According to Bohr's angular momentum equation,

mvr=nh2π

The angular momentum equation for third orbit is

mvr=3h2π

2πr3=hmv

According de Broglie's equation

λ=hmv

 λ=2π9a03=6πa0

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