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If the ratio of the concentration of electrons that of holes in a semiconductor is $\frac{7}{5}$ and the ratio of currents is $\frac{7}{4}$, then what is the ratio of their drift velocities?
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$\frac{5}{4}$
$\frac{5}{4}$
$\frac{\mathrm{n}_{\mathrm{e}}}{\mathrm{n}_{\mathrm{n}}}=\frac{7}{5} \frac{\mathrm{l}_{\mathrm{e}}}{\mathrm{l}_{\mathrm{n}}}=\frac{7}{4}$
$\frac{\left(\mathrm{V}_{\mathrm{d}}\right)_{\mathrm{e}}}{\left(\mathrm{V}_{\mathrm{d}}\right)_{\mathrm{n}}} \Rightarrow \frac{\mathrm{l}_{\mathrm{e}}}{\mathrm{l}_{\mathrm{n}}} \times \frac{\mathrm{n}_{\mathrm{n}}}{\mathrm{n}_{\mathrm{e}}}=\frac{5}{4}$
$\frac{\left(\mathrm{V}_{\mathrm{d}}\right)_{\mathrm{e}}}{\left(\mathrm{V}_{\mathrm{d}}\right)_{\mathrm{n}}} \Rightarrow \frac{\mathrm{l}_{\mathrm{e}}}{\mathrm{l}_{\mathrm{n}}} \times \frac{\mathrm{n}_{\mathrm{n}}}{\mathrm{n}_{\mathrm{e}}}=\frac{5}{4}$
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