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If the reading in Fahrenheit scale is twice the reading in Celsius scale, then the reading in Fahrenheit scale is
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$320^{\circ} \mathrm{F}$
$\begin{aligned} & \text { Given } \mathrm{F}=2 \mathrm{C} ; \mathrm{C}=\frac{\mathrm{F}}{2} \\ & \Rightarrow \frac{\mathrm{F}-32}{9}=\frac{\mathrm{C}}{5} \Rightarrow \frac{\mathrm{F}-32}{9}=\frac{\mathrm{F}}{2 \times 5} \\ & \Rightarrow 10 \mathrm{~F}-320=9 \mathrm{~F} \\ & \Rightarrow \mathrm{F}=320^{\circ} \mathrm{F}\end{aligned}$
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