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If the resistance of $0.1 \mathrm{M} \mathrm{KCl}$ solution in a conductance cell is $300 \Omega$ and conductivity is $0.013 \mathrm{Scm}^{-1}$, then the value of cell constant is
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$3.9 \mathrm{~cm}^{-1}$
Conductivity $(\kappa)=\frac{1}{\text { Resistance }(R)} \times$ cell constant Cell constant $=\kappa \times R$
Given, $\kappa=0.0135 \mathrm{~cm}^{-1} \Rightarrow R=300 \Omega$
Cell constant $=0.0135 \times 300=3.9 \mathrm{~cm}^{-1}$.
Given, $\kappa=0.0135 \mathrm{~cm}^{-1} \Rightarrow R=300 \Omega$
Cell constant $=0.0135 \times 300=3.9 \mathrm{~cm}^{-1}$.
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