If the root mean square velocity of hydrogen molecule at a given temperature and pressure is 2 km s - 1 , the root mean square velocity of oxygen at the same condition in km s - 1 is:

Question

If the root mean square velocity of hydrogen molecule at a given temperature and pressure is 2 km s - 1 , the root mean square velocity of oxygen at the same condition in km s - 1 is:, 2 . 0, 0 . 5, 1 . 5, 1 . 0

MARKS App · Accepted Answer

Root mean square velocity is given by, V r m s = 3 R T M Therefore, V 1 V 2 = M 2 M 1 ⇒ 2 V 2 = 32 2 ⇒ V 2 = 0 . 5 km s - 1

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