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If the roots of the equation $3 x^{2}-5 x+q=0$ are equal, then what is the value of $q$ ?
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The correct answer is:
$25 / 12$
Givenquadratic equation is $3 x^{2}-5 x+q=0$
Since, roots of this equation are equal therefo $b^{2}-4 a c=0$
$\Rightarrow(-5)^{2}-4(3)(q)=0$
$\Rightarrow 25-12 q=0$
$\Rightarrow q=\frac{25}{12}$
Since, roots of this equation are equal therefo $b^{2}-4 a c=0$
$\Rightarrow(-5)^{2}-4(3)(q)=0$
$\Rightarrow 25-12 q=0$
$\Rightarrow q=\frac{25}{12}$
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