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Question: Answered & Verified by Expert
If the roots of the equation $x^{2}-n x+m=0$ differ by 1, then
MathematicsQuadratic EquationNDANDA 2015 (Phase 2)
Options:
  • A $\mathrm{n}^{2}-4 \mathrm{~m}-1=0$
  • B $\mathrm{n}^{2}+4 \mathrm{~m}-1=0$
  • C $\quad \mathrm{m}^{2}+4 \mathrm{n}+1=0$
  • D $\mathrm{m}^{2}-4 \mathrm{n}-1=0$
Solution:
2401 Upvotes Verified Answer
The correct answer is: $\mathrm{n}^{2}-4 \mathrm{~m}-1=0$
Let the root be $\alpha$ and $\beta$ $x^{2}-n x+m=0$
$\Rightarrow \alpha+\beta=n ; \alpha . \beta=\mathrm{m}$
$\alpha-\beta=$
$\Rightarrow(\alpha+\beta)^{2}=(\alpha-\beta)^{2}+4 \alpha \beta$
$\Rightarrow \mathrm{n}^{2}=1+4 \mathrm{~m}$
- $n^{2}-4 m-1=0$

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