Search any question & find its solution
Question:
Answered & Verified by Expert
If the scattering intensity of a liquid is 8 units at a wavelength of $500 \mathrm{~nm}$, then the scattering intensity at a wavelength of $400 \mathrm{~nm}$ will be approximately
Options:
Solution:
2647 Upvotes
Verified Answer
The correct answer is:
20 units
Intensity,
$$
\begin{aligned}
&I \propto \frac{1}{\lambda^{4}} \\
&\frac{I_{2}}{I_{1}}=\left(\frac{\lambda_{1}}{\lambda_{2}}\right)^{4} \\
&\frac{I_{2}}{I_{1}}=\left(\frac{500}{400}\right)^{4} \cong 2.5 \\
&I_{2}=2.5 I_{1}=2.5 \times 8 \\
&I_{2}=20.5 \approx 20 \text { units }
\end{aligned}
$$
$$
\begin{aligned}
&I \propto \frac{1}{\lambda^{4}} \\
&\frac{I_{2}}{I_{1}}=\left(\frac{\lambda_{1}}{\lambda_{2}}\right)^{4} \\
&\frac{I_{2}}{I_{1}}=\left(\frac{500}{400}\right)^{4} \cong 2.5 \\
&I_{2}=2.5 I_{1}=2.5 \times 8 \\
&I_{2}=20.5 \approx 20 \text { units }
\end{aligned}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.