If the series limit wavelength of the Lyman series of hydrogen atom is 912 Å , then the series limit wavelength of the Balmer series of the hydrogen atom is

Question

If the series limit wavelength of the Lyman series of hydrogen atom is 912 Å , then the series limit wavelength of the Balmer series of the hydrogen atom is, 912 Å, 1824 Å, 3648 Å, 456 Å

MARKS App · Accepted Answer

For series limit of Balmer series, n 2 = 2 , n 1 = ∞ 1 λ = R 1 n 2 2 - 1 n 1 2 = 1 2 2 - 1 ∞ 2 = R 4 ∴ λ = 4 R = 4 10967800 m = 4 × 912 × 10 - 10 m = 3648 Å

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