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If the sides of a triangle $\mathrm{ABC}$ whose perimeter is 42 are in arithmetic progression, its circum-radius is $\frac{65}{8}$ and $\mathrm{B} < \mathrm{A} < \mathrm{C}$, then $\sin \mathrm{A}=$
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The correct answer is:
$\frac{56}{65}$
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