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If the solubility of a sparingly soluble salt of the type $B A_2$ (giving three ions on dissociation of a molecule) is $x$ moles per litre, then its solubility product is given by
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The correct answer is:
$4x^3$
By formula $B A_2 \rightarrow B^{+}+2 A^{-}$
$K_{s p}=4 x^3$
$K_{s p}=4 x^3$
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