Given lines can be rewritten as
$\frac{x-1}{1}=\frac{y+3}{-\mathrm{\lambda }}=\frac{z-1}{\mathrm{\lambda }}=s$
$\mathrm{a}\mathrm{n}\mathrm{d}\mathrm{ }\frac{x-0}{1}=\frac{y-1}{2}=\frac{z-2}{-2}=\frac{t}{2}$

As we know that  for coplaner lines determinant formed by elements of direction ratio of lines must be zero.
$\therefore \left|\begin{array}{ccc}1-0& -3-1& 1-2\\ 1& -\mathrm{\lambda }& \mathrm{\lambda }\\ 1& 2& -2\end{array}\right|=0$
$\Rightarrow \left|\begin{array}{ccc}1& -4& -1\\ 1& -\mathrm{\lambda }& \mathrm{\lambda }\\ 1& 2& -2\end{array}\right|=0$
$\Rightarrow 1\left(2\mathrm{\lambda }-2\mathrm{\lambda }\right)+4\left(-2-\mathrm{\lambda }\right)-1\left(2+\mathrm{\lambda }\right)=0$
$\Rightarrow -8-4\mathrm{\lambda }-2-\mathrm{\lambda }=0$
$\Rightarrow \mathrm{\lambda }=-2$