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If the sum of the coefficients in the expansion of $(a+b)^n$ is 4096 , then the greatest coefficient in the expansion is
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The correct answer is:
924
924
We have $2^n=4096=2^{12} \Rightarrow n=12$; So middle term $=t_7 ; t_7=t_{6+1}={ }^{12} C_6=\frac{12 !}{6 ! 6 !}=924$
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