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If the surface tension of a soap solution is $3 \times 10^{-2} \mathrm{~N} / \mathrm{m}$, then the work done in
forming a soap film of $20 \mathrm{~cm} \times 5 \mathrm{~cm}$ will be
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forming a soap film of $20 \mathrm{~cm} \times 5 \mathrm{~cm}$ will be
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Verified Answer
The correct answer is:
$6 \times 10^{-4} \mathrm{~J}$
(C)
$\begin{aligned} W &=2 T \times A \\ &=2 \times 3 \times 10^{-2} \times 100 \times 10^{-4} \\ &=6 \times 10^{-4} \mathrm{~J} \end{aligned}$
$\begin{aligned} W &=2 T \times A \\ &=2 \times 3 \times 10^{-2} \times 100 \times 10^{-4} \\ &=6 \times 10^{-4} \mathrm{~J} \end{aligned}$
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