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If the system of equation
$3 x-2 y+z=0, \quad \lambda x-14 y+15 z=0, \quad x+2 y+3 z=0$
have a non-trivial solution, then $\lambda=$
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$3 x-2 y+z=0, \quad \lambda x-14 y+15 z=0, \quad x+2 y+3 z=0$
have a non-trivial solution, then $\lambda=$
Solution:
1682 Upvotes
Verified Answer
The correct answer is:
29
If the given system of equations has a non-trivial solution, then $\left|\begin{array}{ccc}3 & -2 & 1 \\ \lambda & -14 & 15 \\ 1 & 2 & 3\end{array}\right|=0 \Rightarrow \lambda=29$
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