Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If the tangent to the circle $x^2+y^2-4 x+2 y-5=0$ at $(3,-4)$ cuts the circle $x^2+y^2+16 x+2 y+10=0$ at $A$ and $B$, then the mid point of $A B$ is:
MathematicsCircleAP EAMCETAP EAMCET 2018 (24 Apr Shift 2)
Options:
  • A $(-6,-9)$
  • B $(-9,-6)$
  • C $(-6,-7)$
  • D $(-7,-6)$
Solution:
1700 Upvotes Verified Answer
The correct answer is: $(-6,-7)$
No solution. Refer to answer key.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.