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If the third term of a G.P. is 4 then the product of its first 5 terms is
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Verified Answer
The correct answer is:
$4^5$
Given that $a r^2=4$
Then product of first 5 terms
$=a(a r)\left(a r^2\right)\left(a r^3\right)\left(a r^4\right)=a^5 r^{10}=\left[a r^2\right]^5=4^5$
Then product of first 5 terms
$=a(a r)\left(a r^2\right)\left(a r^3\right)\left(a r^4\right)=a^5 r^{10}=\left[a r^2\right]^5=4^5$
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