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If the total number of m-element subsets of the set $\mathrm{A}=\left\{\mathrm{a}{1}, \mathrm{a}{2}, \ldots . \mathrm{a}{\mathrm{n}}\right\}$ is $\mathrm{k}$ times the number of $\mathrm{m}$ element subsets containing $\mathrm{a}{4}$, then $\mathrm{n}$ is
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Verified Answer
The correct answer is:
$\mathrm{mk}$
Hint:
$n_{c_{m}}=k^{n-1} c_{m-1} \Rightarrow n=m k$
$n_{c_{m}}=k^{n-1} c_{m-1} \Rightarrow n=m k$
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