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If the two slits in Young's double slit experiment are of unequal width, then
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the dark fringes are not perfectly dark
If $I_{1} \neq I_{2}$, then minimum energy of the interference pattern,
$I_{\min }=\left(\sqrt{I_{1}}-\sqrt{I_{2}}\right)^{2}$ is not zero.
Hence, dark fringes are not perfectly dark.
$I_{\min }=\left(\sqrt{I_{1}}-\sqrt{I_{2}}\right)^{2}$ is not zero.
Hence, dark fringes are not perfectly dark.
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