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Question: Answered & Verified by Expert
If the vector b=3j^+4k^ is written as the sum of a vector b1, parallel to a= i^+ j^ and a vector b2, perpendicular to a, then b1×b2 is equal to :
MathematicsVector AlgebraJEE MainJEE Main 2017 (09 Apr Online)
Options:
  • A 6i^-6j^+92k^
  • B -3i^+3j^-9k^
  • C -6i^+6j^-92k^
  • D 3i^-3j^+9k^
Solution:
1847 Upvotes Verified Answer
The correct answer is: 6i^-6j^+92k^


b1=b  aa^2

=3j^+4k^i^+ j^2 i^+ j^2

=3i^+ j^2×2=3i^+ j^2

b1+b2= b

b2= b- b1

=3j^+4k^-32i^+ j^

b2= -32i^+32j^+4k^

b1×b2=i^j^k^32320-32324

i^6- j^6+ k^94+94=6i^-6j^+92k^

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