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If the velocity of sound in air is $350 \mathrm{~m} / \mathrm{s}$. Then the fundamental frequency of an open organ pipe of length $50 \mathrm{~cm}$, will be
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350 Hz
Given $; l=50 \mathrm{~cm}, v=350 \mathrm{~m} / \mathrm{s}$
Fundamental frequency of open pipe
$\nu=\frac{v}{2 l}=\frac{350}{2 \times 0.5}=350 \mathrm{~Hz}$
Fundamental frequency of open pipe
$\nu=\frac{v}{2 l}=\frac{350}{2 \times 0.5}=350 \mathrm{~Hz}$
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