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If the Wheatstone's bridge with four resistors $R_1, R_2$ and $R_3, R_4$ is balanced, then the correct expression is

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The correct answer is:
$\frac{R_2}{R_1}=\frac{R_4}{R_3}$

For balance condition of Wheatstone bridge,
$\frac{R_2}{R_4}=\frac{R_1}{R_3} \quad \text { or } \quad \frac{R_2}{R_1}=\frac{R_4}{R_3}$
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