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Question: Answered & Verified by Expert
If the work function for the photoelectron emission of a metal is 3.75eV, then the threshold wave length of the radiation needed for the ejection of the electron is approximately
ChemistryStructure of AtomAP EAMCETAP EAMCET 2021 (20 Aug Shift 2)
Options:
  • A 315 nm
  • B 280 nm
  • C 330 nm
  • D 290 nm
Solution:
2158 Upvotes Verified Answer
The correct answer is: 330 nm

Work function of metal ϕ=3.75 eV=3.75×1.6×10-19V=6×10-19V

Planck's constant h=6.63×10-34J.s

Velocity of light c=3×108 m/s

Wavelength = hcϕ=6.63×10-34×3×1086×10-19=331.5 ×10-9m=331.5 nm

Hence, the threshold wave length of the radiation needed for the ejection of the electron is approximately 330 nm.

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