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If three unbiased dice are rolled simultaneously then the probability that all the three dice show distinct numbers is
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Verified Answer
The correct answer is:
$\frac{5}{9}$
Total number of elements in sample space
$$
=6 \times 6 \times 6=216
$$
Ways to get different numbers on all 3 dice
$$
=6 \times 5 \times 4=120
$$
$\therefore \quad$ Probability $=\frac{120}{216}=\frac{5}{9}$.
$$
=6 \times 6 \times 6=216
$$
Ways to get different numbers on all 3 dice
$$
=6 \times 5 \times 4=120
$$
$\therefore \quad$ Probability $=\frac{120}{216}=\frac{5}{9}$.
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