Search any question & find its solution
Question:
Answered & Verified by Expert
If truth values of $P$ be $F$ and $q$ be $T$. Then, truth value of $\sim(\sim p \vee q)$ is
Options:
Solution:
1853 Upvotes
Verified Answer
The correct answer is:
$\mathrm{F}$
\begin{array}{|c|c|c|c|c|}
\hline \mathbf{p} & \mathbf{q} & \sim \mathbf{p} & \sim \mathbf{p} \vee \mathbf{q} & \sim(\sim \mathbf{p} \vee \mathbf{q}) \\
\hline \mathrm{F} & \mathrm{T} & \mathrm{T} & \mathrm{T} & \mathrm{F} \\
\hline
\end{array}
$\therefore$ Truth value of $\sim(\sim \mathrm{p} \vee \mathrm{q})$ is $\mathrm{F}$.
\hline \mathbf{p} & \mathbf{q} & \sim \mathbf{p} & \sim \mathbf{p} \vee \mathbf{q} & \sim(\sim \mathbf{p} \vee \mathbf{q}) \\
\hline \mathrm{F} & \mathrm{T} & \mathrm{T} & \mathrm{T} & \mathrm{F} \\
\hline
\end{array}
$\therefore$ Truth value of $\sim(\sim \mathrm{p} \vee \mathrm{q})$ is $\mathrm{F}$.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.