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If two dice are thrown, then what is the probability that the sum on the two faces is greater than or equal to $4$ ?
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Verified Answer
The correct answer is:
$\frac{11}{12}$
Since two dice are thrown so number of outcomes are $36 .$
No. of ways when sum on two faces less than $4=3$. $[(1,1),(1,2),(2,1)]$
Hence prob of getting sum on two faces less than 4
$$
=\frac{3}{36}=\frac{1}{12}
$$
Thus required prob. that sum on the two faces is greater
than or equal to $4=1-\frac{1}{12}=\frac{11}{12}$
No. of ways when sum on two faces less than $4=3$. $[(1,1),(1,2),(2,1)]$
Hence prob of getting sum on two faces less than 4
$$
=\frac{3}{36}=\frac{1}{12}
$$
Thus required prob. that sum on the two faces is greater
than or equal to $4=1-\frac{1}{12}=\frac{11}{12}$
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