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If two dice are thrown together. Then, the probability that the sum of the numbers appearing on them is a prime number, is
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$5 / 12$
Total cases $=36$
Prime number are $2,3,5,7,11$. $\therefore$ Favourable cases $=15$
Required probability $=\frac{15}{36}=\frac{5}{12}$
Prime number are $2,3,5,7,11$. $\therefore$ Favourable cases $=15$
Required probability $=\frac{15}{36}=\frac{5}{12}$
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