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If two fair dice are rolled then what is the conditional probability that the first dice lands on 6 given that the sum of numbers on the dice is 8 ?
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The correct answer is:
$\frac{1}{5}$
Total number of cases that sum is 8 are $(2,6),(3,5),(4,4),(5,3),(6,2)$
favourable case $=(6,2)$
$\therefore$ Probability $=\frac{1}{5}$
favourable case $=(6,2)$
$\therefore$ Probability $=\frac{1}{5}$
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