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If two identical bar magnets, each of length $l$, pole strength $m$ and magnetic moment $M$ are placed perpendicular to each other with their unlike poles in contact, the magnetic moment of the combination is
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Verified Answer
The correct answer is:
$\operatorname{lm}(\sqrt{2})$
When magnets are placed perpendicular to each other then,
Resultant magnetic moment
$M^{\prime}=\sqrt{M_1^2+M_2^2}$
Here,
$M_1=M_2=M$
So,
$M^{\prime}=M \sqrt{2}=m l \sqrt{2}$
$[\because M=m l]$
Resultant magnetic moment
$M^{\prime}=\sqrt{M_1^2+M_2^2}$
Here,
$M_1=M_2=M$
So,
$M^{\prime}=M \sqrt{2}=m l \sqrt{2}$
$[\because M=m l]$
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