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If uncertainty in position and momentum are equal, then uncertainty in velocity is
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Verified Answer
The correct answer is:
$\frac{1}{2 m} \sqrt{\frac{h}{\pi}}$
$\Delta x=\Delta p$
$$
\Delta p^2=\frac{h}{4 \pi}
$$
or $\Delta p=\frac{1}{2} \sqrt{\frac{h}{\pi}}$
or $m \Delta v=\frac{1}{2} \sqrt{\frac{h}{\pi}}$
or $\Delta v=\frac{1}{2 m} \sqrt{\frac{h}{\pi}}$
$$
\Delta p^2=\frac{h}{4 \pi}
$$
or $\Delta p=\frac{1}{2} \sqrt{\frac{h}{\pi}}$
or $m \Delta v=\frac{1}{2} \sqrt{\frac{h}{\pi}}$
or $\Delta v=\frac{1}{2 m} \sqrt{\frac{h}{\pi}}$
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