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If $\mathrm{v}_1$ is the speed of sound in a diatomic gas at $273{ }^{\circ} \mathrm{C}$ and $\mathrm{v}_2$ is the r.m.s. speed of its molecules at $273 \mathrm{~K}$, then $\frac{\mathrm{v}_1}{\mathrm{v}_2}=$
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The correct answer is:
$\sqrt{\frac{14}{15}}$
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