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If \( |\vec{a}|=16,|\vec{b}|=4 \) then, \( \sqrt{|\vec{a} \times \vec{b}|^{2}+|\vec{a} \vec{b}|^{2}} \)
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\( 64 \)
(B)
\( \sqrt{|\vec{a} \times \vec{b}|^{2}+|\vec{a} \vec{b}|^{2}}=\sqrt{|\vec{a}|^{2}|\vec{b}|^{2}}=|\vec{a}||\vec{b}|=(16)(4)=64 \)
\( \sqrt{|\vec{a} \times \vec{b}|^{2}+|\vec{a} \vec{b}|^{2}}=\sqrt{|\vec{a}|^{2}|\vec{b}|^{2}}=|\vec{a}||\vec{b}|=(16)(4)=64 \)
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