If x 0 and x ≠ 2 n + 1 π 2 then ∫ x x - e log sec x tan x + 3 x 2 - 2 x + 1 x 2 d x =

Question

If x > 0 and x ≠ 2 n + 1 π 2 then ∫ x x - e log sec x tan x + 3 x 2 - 2 x + 1 x 2 d x =, x x - sec x + 3 x - 2 log x - 1 x + c, 2 5 x 2 x - sec x + 3 x + 2 x 2 - 1 x + c, x x - sec x + 3 x + 2 x 2 - 1 x + c, 2 5 x 2 x - sec x + 3 x - 2 log x - 1 x + c

MARKS App · Accepted Answer

Let I = ∫ x x - e log sec x tan x + 3 x 2 - 2 x + 1 x 2 d x ⇒ I = ∫ x x - sec x tan x + 3 - 2 x + 1 x 2 d x ⇒ I = 2 5 x 2 x - sec x + 3 x - 2 log x - 1 x + c where, c is the constant of integration.

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