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If $\frac{3 x+5}{(x+1)\left(2 x^2+3\right)}=\frac{\mathrm{A}}{x+1}+\frac{\mathrm{B} x+\mathrm{C}}{2 x^2+3}$ and $f(x)=\mathrm{A} x^3+$ $\mathrm{B} x^2+7 x+\mathrm{C}$, then $5 \mathrm{C}-f^{\prime}(-2)=$
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